Mechanical Properties of a Vertebra Exam Question
What are the randomized variables in a scenario where a vertebra is subjected to a shearing force of 520 N?
a) Force = 520 N, Height = 2.5 cm, Diameter = 4.3 cm
b) Force = 520 N, Height = 4.3 cm, Diameter = 2.5 cm
c) Force = 2.5 cm, Height = 520 N, Diameter = 4.3 cm
d) Force = 520 N, Height = 2.5 cm, Diameter = 4.3 cm
Answer:
The randomized variables in a situation where a vertebra is subjected to a shearing force of 520 N are the force applied, the height of the vertebra, and the diameter of the vertebra.
Explanation: In the context of the question, a vertebra is subjected to a shearing force of 520 N, and the question likely revolves around calculating the shear deformation or stress experienced by the vertebra, given its dimensions. The randomized variables refer to the dimensions of the vertebra, which are necessary for calculating said shear deformation.
The question asks about the randomized variables in a situation where a vertebra is subjected to a shearing force of 520 N. The randomized variables refer to the different factors or properties in the scenario that may affect the outcome. In this case, the correct option is d) Force = 520 N, Height = 2.5 cm, Diameter = 4.3 cm, as the force applied to the vertebra, the height of the cylinder representing the vertebra, and the diameter of the cylinder are all relevant in determining the shear deformation.
Therefore, the answer is d) Force = 520 N, Height = 2.5 cm, Diameter = 4.3 cm.