Calculating Specific Heat of Iron

The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 114.3 J of heat.

Answer:

Q = mc(θ₂-θ₁)

47 calories = 10 g * c * (50.4 - 25)

47 cal = 10 * c * 25.4

47 / (10 * 25.4) = c

0.185 = c

Specific heat of iron = 0.185 cal/g°C

Explanation:

What is the specific heat of iron?

The specific heat of iron is 0.185 cal/g°C.