Magnitude of Electric Field Between Plates of a Parallel Plate Capacitor
How to calculate the magnitude of the electric field between the plates of a parallel plate capacitor?
If a battery of 9 V is connected across a parallel plate capacitor with plate separation of 2 mm, what is the magnitude of the electric field between its plate when it is fully charged?
A. 4500 V/m
B. 9000 V/m
C. 18 V/m
D. 18000 V/m
E. 0 V/m
The magnitude of the electric field between the plates of the capacitor when it is fully charged is 4500 V/m, which corresponds to option A.
To calculate the magnitude of the electric field between the plates of a parallel plate capacitor, you can use the formula: E = V/d.
Where:
E is the electric field
V is the voltage across the capacitor
d is the distance between the plates
In the given scenario, the voltage V is 9 V and the plate separation d is 2 mm, which can be converted to 0.002 m.
By substituting these values into the formula, we can calculate the electric field as follows:
E = 9 V / 0.002 m
E = 4500 V/m
Therefore, the magnitude of the electric field between the plates of the capacitor when it is fully charged is 4500 V/m, which corresponds to option A.
By understanding this calculation, you can gain a better grasp of the concept of electric fields in parallel plate capacitors.