# Discover the Resistance of a Light Bulb in a Circuit!

## How can we determine the resistance of a light bulb in a circuit?

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and the voltmeter reads 6 volts. What is the resistance of the light bulb?

## Answer:

The resistance of the light bulb is **2 ohms.**

In this scenario, Ohm's Law can be applied to calculate the resistance of the light bulb. Ohm's Law states that **Voltage (V) equals Current (I) multiplied by Resistance (R).**

By rearranging the formula to solve for resistance, we get: **R = V / I**

Plugging in the given values of voltage (6 volts) and current (3 amps) into the formula, we find: **R = 6 / 3 = 2 ohms.**

Therefore, the resistance of the light bulb in the circuit is 2 ohms. Understanding how to calculate resistance in a circuit allows us to analyze and optimize the performance of electrical devices. Keep exploring the fascinating world of electronics!