Discover the Resistance of a Light Bulb in a Circuit!

How can we determine the resistance of a light bulb in a circuit?

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and the voltmeter reads 6 volts. What is the resistance of the light bulb?

Answer:

The resistance of the light bulb is 2 ohms.

In this scenario, Ohm's Law can be applied to calculate the resistance of the light bulb. Ohm's Law states that Voltage (V) equals Current (I) multiplied by Resistance (R).

By rearranging the formula to solve for resistance, we get: R = V / I

Plugging in the given values of voltage (6 volts) and current (3 amps) into the formula, we find: R = 6 / 3 = 2 ohms.

Therefore, the resistance of the light bulb in the circuit is 2 ohms. Understanding how to calculate resistance in a circuit allows us to analyze and optimize the performance of electrical devices. Keep exploring the fascinating world of electronics!

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