Calculating the Amount of Phosphoric Acid in mmol
How to calculate the amount of phosphoric acid (H3PO4) in millimoles present in a reaction?
Given the following data:
- Volume of phosphoric acid: 0.1 mL
- Density of phosphoric acid: 1.685 g/mL
- Molecular weight of phosphoric acid: 98 g/mol
Answer:
There are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.
To calculate the amount of phosphoric acid in millimoles (mmoles) present in the reaction, we can use the provided data - the volume of phosphoric acid, its density, and its molecular weight. Here's a step-by-step explanation:
Step 1: Calculate the mass of the phosphoric acid solution
Mass = Volume × Density
Mass = 0.1 mL × 1.685 g/mL
Mass ≈ 0.1685 grams
Step 2: Convert mass to moles using the molecular weight
Moles = Mass / Molecular Weight
Moles = 0.1685 g / 98 g/mol
Moles ≈ 0.001717 moles
Step 3: Convert moles to millimoles
Millimoles ≈ 0.001717 moles × 1000
Millimoles ≈ 1.717 millimoles
Therefore, there are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.