# The Volume of NH₃ Solution Needed for a Specific Mass of Ammonia

## How do we calculate the volume of a 133 ppm NH₃ solution with a density of 0.998 g/ml needed to provide 0.0175 grams of NH₃?

Given data: 133 ppm NH₃ solution, density of 0.998 g/ml, and 0.0175 grams of NH₃

## Calculation:

The volume of a solution is calculated using the formula: volume = (mass of solute / (concentration of solute x density of solution)) x 10⁶

Given: mass of NH₃ = 0.0175 grams, concentration = 133 ppm, density = 0.998 g/ml

Substitute the values into the formula:

volume = (0.0175 / (133 x 0.998)) x 10⁶

volume = 1.3188 liters

The calculation shows that 1.3188 liters of the 133 ppm NH₃ solution with a density of 0.998 g/ml is required to provide 0.0175 grams of ammonia (NH₃). This means that a relatively small volume of the solution is needed to contain the desired mass of NH₃.

Understanding how to calculate the volume of a solution based on its concentration and density is essential in various fields such as chemistry, pharmaceuticals, and environmental science. It allows for accurate measurements and proper handling of substances.

By mastering such calculations, you can efficiently determine the appropriate amounts of substances needed for a specific task, ensuring successful outcomes and minimizing waste. Keep exploring and practicing these calculations to enhance your skills and knowledge in the field of chemistry!