What is the work required to move a 900 N crate at a constant velocity 6.0 m along the floor against a friction force of 180 N?
The work required to move the crate at a constant velocity 6.0 m along the floor against a friction force of 180 N is 1080 J.
Calculating Work Required
Work is defined as the product of the force applied on an object and the distance over which the force is applied. In this scenario, we are moving a 900 N crate against a friction force of 180 N for a distance of 6.0 m.
To calculate the work required, we use the formula:
Work = force * distance * cos(theta)
Given that:
- Force (friction force) = 180 N
- Distance = 6.0 m
- Cosine of the angle between force and displacement = 1 (as they are in the same direction)
Plugging in the values:
Work = 180 N * 6.0 m * 1 = 1080 J
Therefore, the work required to move the crate at a constant velocity 6.0 m along the floor against a friction force of 180 N is 1080 J. The correct answer is d) 10800 J.