Stunt Bike Velocity Calculation
When a stunt bike leaves a ramp at 100 km/hr and at an angle of 35 degrees, we can calculate its horizontal and vertical velocities by resolving the velocity vector into its component along the horizontal and vertical direction.
Horizontal Velocity Calculation:
The horizontal velocity of the stunt bike can be calculated using the formula:
vx = v cos θ
where:
v = 100 km/h is the magnitude of the velocity
θ = 35 degrees is the angle of projection
Substituting the values, we find:
vx = (100) * (cos 35 degrees) = 81.9 km/h
Vertical Velocity Calculation:
The vertical velocity of the stunt bike can be calculated using the formula:
vy = v sin θ
where:
v = 100 km/h
θ = 35 degrees
Substituting the values, we find:
vy = (100) * (sin 35 degrees) = 57.4 km/h
By calculating the horizontal and vertical velocities, we can understand the motion of the stunt bike as it leaves the ramp. The horizontal velocity determines the speed of the bike moving along the ground, while the vertical velocity indicates the rate at which the bike is moving upwards or downwards.
Understanding how to calculate the horizontal and vertical velocities of an object in motion is essential in physics and engineering, as it helps in analyzing the trajectory and motion of objects in different scenarios.