Resistance Calculation in Circuit with Ammeter Reading
What is the resistance of the light bulb in the circuit?
The resistance of the light bulb in the circuit is 15 ohms. How can we calculate this value?
Calculation of Resistance Value
The resistance of the light bulb in the circuit can be calculated using Ohm's Law, which relates voltage, current, and resistance in an electrical circuit.
Given:
Voltage (V) = 12 volts
Current (I) = 0.80 amperes
To find the resistance (R), we can use the formula R = V / I.
Substitute the values into the formula:
Resistance (R) = 12 volts / 0.80 amperes = 15 ohms
Therefore, the resistance of the light bulb in the circuit is 15 ohms when a 12-volt potential difference is applied and a current of 0.80 amperes flows through it.
Resistance is a crucial parameter in electrical circuits that determines the flow of current. In this scenario, we have a 12-volt battery and a light bulb connected in series. The ammeter reading indicates a current of 0.80 amperes passing through the circuit.
By applying Ohm's Law, we can determine that the resistance of the light bulb is 15 ohms. This means that for the given voltage and current values, the light bulb impedes the flow of electricity with a resistance of 15 ohms.
Understanding how to calculate resistance values in circuits is essential for analyzing and troubleshooting electrical systems. By knowing the relationship between voltage, current, and resistance, engineers and technicians can effectively design and maintain various electrical installations.