Reflection on Distance and Time Calculation

What times is the car 0.1 miles from the checkpoint?

a) 95.1s and 108.7s
b) 10.2s and 101.9s
c) 108.7s and 10.2s
d) 95.1s and 10.2s

For the answer to the question above, To be 0.1 miles away from the checkpoint, the car has to travel 1.4 miles OR 1.6 miles. 53 miles = 60 minutes. 1.4 miles = 1.4 / 53 X 60 = 1.5849056 minutes OR 95.1 seconds. 1.6 miles = 1.6 /53 X 60 = 1.8113207 minutes OR 108.7 seconds. So the answer is 95.1s and 108.7s. I hope my answer helped you.

Reflecting on the distance and time calculation question provided, it is fascinating to see how the concept of speed and distance can be interlinked in such a practical scenario. In this particular case, we are given a situation where a car is traveling at a constant rate of 53 miles per hour towards a speed checkpoint.

The formula d = |1.5 – 53t| is used to calculate the distance of the car from the checkpoint at any given time 't'. To determine the times when the car is 0.1 miles away from the checkpoint, we need to substitute d = 0.1 into the equation and solve for 't'.

By performing the necessary calculations, we find that the car will be 0.1 miles away from the checkpoint at 95.1 seconds and 108.7 seconds. This showcases the importance of understanding mathematical concepts in real-world situations and how they can be applied to solve problems effectively.

← Work done by aiden Exploring newton s third law of motion →