Light Up Your Day with This Exciting Physics Problem!

How bright is a 100W light bulb with a 220V AC supply of 50Hz?

Are you ready to calculate the resistance of the light bulb?

Let's Shed Some Light on This!

When it comes to calculating the resistance of a light bulb, we can use Ohm's Law. In this case, the resistance of the bulb is 484 Ohms.

The specified data provides us with the power rating of the light bulb, which is 100W, and the voltage supply of 220V AC at a frequency of 50Hz. To find the resistance of the bulb, we need to apply Ohm's Law, which relates the power, voltage, and resistance in a circuit.

Ohm's Law formula is P = V^2 / R, where P is power, V is voltage, and R is resistance. By rearranging the formula, we can solve for the resistance: R = V^2 / P. Substituting the given values, we get R = (220V)^2 / 100W = 484Ω.

It's important to note that the frequency of 50Hz does not impact the resistance calculation for an incandescent bulb like this one. The resistance of such bulbs is independent of frequency, unlike components like capacitors or inductors.

Now that we've brightened up our understanding of this physics problem, you can shine a light on your knowledge by exploring more about the resistance of a light bulb.