Ice Formation: Calculating Mass and Volume

What is the mass and volume of the ice formed when 0.6 L of water at 25 degrees C (density = 0.997 g/mL) is cooled to -10 degrees C to form ice (density = 0.917 g/mL)? The mass of the ice remains the same as the mass of the water, which is 598.2 g. However, the volume of the ice changes to 652.36 mL due to the decreased density of ice.

Understanding Ice Formation

When water is cooled below its freezing point, it solidifies into ice. In this scenario, we start with 0.6 liters of water at 25 degrees Celsius with a density of 0.997 g/mL. The water is then cooled to -10 degrees Celsius to form ice, which has a density of 0.917 g/mL.

To calculate the mass and volume of the ice formed, we first determine the mass of the water. The formula for mass is Mass = Volume * Density. Plugging in the values: Mass = 0.6 L * 0.997 g/mL = 598.2 g. This is the initial mass of the water.

When the water freezes into ice, the mass of the ice will remain the same as the mass of the water, which is 598.2 g. This is because mass is a conserved quantity.

As the density of ice is lower than that of water, the volume of the ice will increase. To calculate the volume of the ice, we rearrange the density formula to find Volume = Mass / Density. Substituting the known values: Volume = 598.2 g / 0.917 g/mL = 652.36 mL.

Therefore, the mass of the ice formed is 598.2 g, and the volume is 652.36 mL. This demonstrates the relationship between density, mass, and volume when water freezes into ice.

← Finding maximum shear stress in a box beam Calculating momentum of a car →

More Posts: