How Far Did Jason Land After Driving Off a Cliff as a Stunt Driver?

Jason landed approximately 30.6 meters from the bottom of the cliff.

To determine the distance Jason landed from the bottom of the cliff, we can use the equation of motion: distance = initial velocity * time + (0.5 * acceleration * time^2). Since Jason fell freely in the vertical direction with an acceleration due to gravity of approximately 9.8 m/s^2, we can calculate the distance using the values provided.

Plugging in the values into the equation, we get: distance = 25 m/s * 1.2 s + (0.5 * 9.8 m/s^2 * (1.2 s)^2) = 30.6 m. Therefore, Jason landed approximately 30.6 meters from the bottom of the cliff.

So, after driving off the cliff as a stunt driver, Jason landed at a distance of approximately 30.6 meters from the bottom of the cliff. It was an impressive stunt that showcased his skills and bravery!