How does the acceleration of a hummingbird change when it speeds up?

What is the acceleration of the hummingbird when it speeds up from 3.00 m/s to 6.50 m/s in 0.0200 seconds?

Calculating acceleration of the hummingbird:

Given data:

Initial speed (u) = 3.00 m/s

Final speed (v) = 6.50 m/s

Time taken (t) = 0.0200 seconds

Using the formula:

v = u + at

Substitute the values:

6.50 = 3.00 + a * 0.0200

Solve for acceleration (a):

6.50 = 3.00 + 0.0200a

0.0200a = 3.50

a = 3.50 / 0.0200

a = 17.5 m/s²

Therefore, the acceleration of the hummingbird when it speeds up from 3.00 m/s to 6.50 m/s in 0.0200 seconds is 17.5 m/s².

← Understanding thrust in turbojet engines Calculating voltage across a resistor in a series circuit →

More Posts: