Exciting Speedboat Journey Ahead!

What is the velocity of the boat when it reaches the buoy?

A speedboat moving at 31.0 m/s approaches a buoy marker 86.0 m ahead. The pilot slows the boat with a constant acceleration of -3.70 m/s² by reducing the throttle. What is the velocity of the boat when it reaches the buoy?

Final Answer:

The question is about a speedboat slowing down to approach a buoy. Using a specific kinematic equation that connects final velocity, initial speed, acceleration, and distance, you can calculate the final speed of the speedboat.

Explanation:

The problem asked is a kinematic equation problem, which relates distance, initial speed, final velocity, acceleration, and time. Looking at the given, the initial speed u is 31.0 m/s, the distance traveled d is 86.0 m and the acceleration a is -3.70 m/s². We need to know the final velocity v of the speedboat when it reaches the buoy.

The equation that best fits this is v² = u² + 2*a*d. Substituting the given values into the equation, we'll have:

v² = (31.0 m/s)² + 2*(-3.70 m/s²)*(86.0 m)

To find the final velocity (v), take the square root of the result above. Please note that a negative velocity would mean the boat is moving in the opposite direction, which is not possible in this scenario.

← The variation of reaction force when decelerating an overhead barbell Quantum mechanics understanding operator momentum and position →