Exciting Physics Problem: Ball Thrown Vertically Upwards!

What happens when a ball is thrown vertically upwards with a velocity of 10m/s from a tall building's balcony 15m above the ground with gravitational acceleration of 10m/s square? The time required for the ball to hit the ground is approximately 1.8 seconds. The velocity with which it hits the ground is approximately 28 m/s.

Understanding the Physics Behind the Ball Thrown Vertically Upwards

When a ball is thrown vertically upwards from a certain height, there are a few key physics concepts at play here. The ball's initial velocity, the gravitational acceleration, and the distance from the balcony to the ground all contribute to the ball's motion.

Using the equation h = ut + (1/2)gt^2, where h is the vertical distance, u is the initial velocity, g is the acceleration due to gravity, and t is the time, we can calculate the time required for the ball to hit the ground.

Substituting the given values into the equation, we get:

15 = 10t + (1/2)(10)t^2

After solving the quadratic equation, we find that the time required for the ball to hit the ground is approximately 1.8 seconds.

Similarly, using the equation v = u + gt, we can calculate the velocity with which the ball hits the ground by substituting the values:

v = 10 + (10)(1.8)

After evaluating, we find that the velocity with which the ball hits the ground is approximately 28 m/s. This showcases the fascinating world of physics and the dynamics of objects in motion!

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