What is the velocity of the ball as it strikes the ground?
Answer:
20.65 m/s
Explanation: When the student throws the ball vertically downward from a height of 15.6 m above the street with an initial velocity of 10.7 m/s, we can calculate the velocity of the ball as it strikes the ground using the equations of motion.
Using the third equation of motion, which is v² - u² = 2ah, where:
- h = 15.6 m (height)
- u = 10.7 m/s (initial velocity)
- a = 10 m/s² (acceleration due to gravity)
Substituting the values into the equation:
v² - (10.7)² = 2(10)(15.6)
v² - 114.49 = 312
v² = 426.49
v = √426.49
v = 20.65 m/s
Therefore, the velocity of the ball as it strikes the ground is 20.65 m/s.