A Car's Acceleration Calculation

A car starts from rest and accelerates uniformly for a distance of 204 m over a 6.5-second time interval. The car's acceleration is _____ m/s².

Answer: 8.10m/s²

Explanation:

Using the second equation of motion: s = ut + 1/2at²

As initial velocity (u) = 0, the equation simplifies to:

s = 1/2at²

204 = 1/2 * a * (6.5)²

408 = a * (42.25)

a = 408 / 42.25

a = 9.63 m/s²

What is the acceleration of the car? The acceleration of the car is 9.63 m/s².
← A lesson in pressure the importance of distribution Vectors lab hands on experience with vector quantities →