What is the proper position for the Seated Barbell Triceps Extension exercise?
Calculating the Moment of Inertia
The torque equation: Ï = Iα
Given values: Force (F) = 2.00 à 10³ N, Lever arm distance (r) = 0.03 m, Angular acceleration (α) = 120 rad/s²
The question asks to calculate the moment of inertia of a boxer's forearm using the information provided about the force exerted by the triceps muscle and the resulting angular acceleration. To find the moment of inertia, we can use the equation Ï = Iα, where Ï is the torque, I is the moment of inertia, and α is the angular acceleration.
The torque (Ï) can be calculated by multiplying the force exerted by the muscle (F) by the effective perpendicular lever arm distance (r), which gives Ï = F à r. Given that F = 2.00 à 10³ N and r = 0.03 m, the torque is calculated as Ï = (2.00 à 10³ N) à (0.03 m) = 60 N·m.
With the angular acceleration (α) given as 120 rad/s², we can rearrange the torque equation to solve for the moment of inertia: I = Ï/α. Plugging in the values gives us I = 60 N·m / 120 rad/s², resulting in a moment of inertia of 0.5 kg·m² for the boxer's forearm.