Determination of Average Shearing Stress in Bolts

What is the average shearing stress in the bolts caused by a shearing force of 25 kN parallel to the y-axis?

Calculation of Average Shearing Stress:

Given:

Shearing force = 25 kN = 25,000 N

Bolt diameter = 20 mm

Bolt radius (r) = 10 mm = 0.01 m

Number of bolts = 4 (2 bolts per channel shape)

Channel shape = C100 x 8

Plate dimension = 250 mm x 15 mm

Bolt spacing = 150 mm

Shear Area of One Bolt:

Shear area (A) = πr^2

Plugging in the values: A = π(0.01)^2 = 0.000314 m^2

Total Shear Area:

Total shear area = 4 bolts * 0.000314 m^2 = 0.001256 m^2

Calculation of Average Shearing Stress:

Average shearing stress = force/area

Substitute the values: stress = 25,000 N / 0.001256 m^2 = 19,913.42 N/m^2 or 19.91 MPa

Summary:

Therefore, the average shearing stress in the bolts caused by a shearing force of 25 kN parallel to the y-axis is 19.91 MPa. This calculation was based on the shear area of one bolt, the total shear area considering all bolts, and using the formula stress = force/area.

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