What would the following Python code print out?

Python Code Output

stuff = dict()
print(('candy',-1))

Final answer: The Python code ('candy', -1) will print a tuple ('candy', -1) as it is.

Explanation: The given code ('candy', -1) in Python represents a tuple, which is immutable and can hold multiple objects of different types. In this case, the tuple consists of a string 'candy' and an integer -1. This bit of code does not have anything to do with the initialized dictionary stuff in the same line. So, when you execute print(('candy', -1)) Python will simply output this tuple as it is, i.e., ('candy', -1).

The provided Python code will print: ('candy', -1)

The code creates an empty dictionary called stuff, but it doesn't actually use this dictionary. Instead, it prints a tuple ('candy', -1) to the console. This tuple contains two elements: the string 'candy' and the integer -1. When you print this tuple, it will display the values as shown.

What is the output of the Python code provided above? The output of the Python code is a tuple with the values ('candy', -1).
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