What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature pressure?

Calculation of Volume of Ammonia Gas

When given the quantity of a gas in moles, it is possible to calculate the volume of the gas by using the Ideal Gas Law equation:

PV = nRT

Where:

P = Pressure

V = Volume

n = Number of moles

R = Ideal Gas Constant

T = Temperature

Given:

Number of moles (n) = 3.50 mol

Standard Temperature (T) = 273 K

Standard Pressure (P) = 1 atm

Ideal Gas Constant (R) = 0.0821 L•atm/mol•K

Let's substitute the given values into the Ideal Gas Law equation:

1 atm * V = 3.50 mol * 0.0821 L•atm/mol•K * 273 K

V = (3.50 * 0.0821 * 273) / 1

V = 78.4 L

Therefore, the volume that 3.50 mol of ammonia gas will occupy at conditions of standard temperature pressure is 78.4 liters.

What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature pressure? C - 78.4L
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