Volume Calculation in Acid-Base Neutralization Reaction
Calculating the Volume of Potassium Hydroxide Solution Needed
When calculating the volume of a solution needed to neutralize another solution in an acid-base reaction, we can use the formula: (Ca x Va)/(Cb x Vb) = Na/Nb
Given Data:
Volume of KOH Vb = ?
Concentration of KOH Cb = 0.149 M
Volume of HBr Va = 17.0 ml
Concentration of HBr Ca = 0.112 M
Equation:
HBr(aq) + KOH(aq) → KBr(aq) + H2O(l)
Mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; Nb, number of moles of KOH is 1)
Solution:
(Ca x Va)/(Cb x Vb) = Na/Nb
(0.112 x 17.0)/(0.149 x Vb) = 1/1
1.904 = 0.149Vb
Vb = 1.904/0.149
Vb = 12.78 ml
Therefore, 12.78 ml of potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 M hydrobromic acid solution.
what volume of a 0.149 M potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 M hydrobromic acid solution? Answer: 12.78 ml