The Volume of Water in a Solar Energy Unit

Calculating the Volume of Water:

Given data:
Initial temperature of the water = 23.4°C
Final temperature of the water = 39°C
Heat absorbed by the water = 2.55 x 10^7 J
Density of water = 0.998 g/mL
Specific heat of water = 4.184 J/g°C

Calculations:
Temperature change, ΔT = 39°C - 23.4°C = 15.6°C
Using the formula q = mCΔT:
2.55 x 10^7 J = m x 4.184 J/g°C x 15.6°C
Solving for mass, m = 390682.45 grams
Density = mass / volume
0.998 g/mL = 390682.45 g / volume
Volume = 391465.38 mL

Therefore, the volume of water in the tank of the home solar energy unit is approximately 391.46 liters.

← Balanced neutralization equation for sodium hydroxide and hydrochloric acid Understanding enzyme kinetics calculating km and vmax →