# How to Calculate the Mass of Hydrogen Gas Needed to Inflate a Baggie

## Calculating the Mass of Hydrogen Gas Needed

**It is desired to inflate a baggie with a volume of 849 milliliters by filling it with hydrogen gas at a pressure of 1.49 atm and a temperature of 286 K. How many grams of H2 gas are needed?**

Final answer: The number of grams of hydrogen gas needed is approximately 0.0739 grams.

Explanation:

To calculate the mass of hydrogen gas needed, we can use the ideal gas law equation: PV = nRT

First, we need to convert the volume from milliliters to liters:

849 milliliters = 0.849 liters

Next, we can rearrange the ideal gas law equation to solve for the number of moles (n): n = PV / RT

Plugging in the given values:

n = (1.49 atm) * (0.849 L) / [(0.0821 L·atm/mol·K) * (286 K)]

Simplifying the equation:

n = 0.0367 moles

Finally, we can calculate the mass of hydrogen gas by multiplying the number of moles by the molar mass of hydrogen gas:

Mass = (0.0367 moles) * (2.016 grams/mol) = 0.0739 grams

It is desired to inflate a baggie with a volume of 849 milliliters by filling it with hydrogen gas at a pressure of 1.49 atm and a temperature of 286 K. How many grams of H2 gas are needed? The number of grams of hydrogen gas needed is approximately 0.0739 grams. To calculate this, we used the ideal gas law equation PV = nRT and converted the volume to liters, found the number of moles, and then calculated the mass by multiplying the moles with the molar mass of hydrogen gas.