How Many Grams of Solute are Required to Make a Sodium Hydroxide Solution?

Calculating the Amount of Solute Needed

Final answer: Approximately 9.836 grams of sodium hydroxide are required to make a 701 ml solution with a concentration of 0.3506 M.

Explanation: The amount of solute required in grams can be calculated using the formula for molarity (M), which is moles of solute divided by volume of solution in liters. Here, the volume is 701 mL or 0.701 L (since 1 L = 1000 mL) and the molarity (M) is 0.3506 M. The number of moles of the solute, in this case sodium hydroxide, is M x V = 0.3506 M x 0.701 L = 0.2459 moles. We know that the molar mass of sodium hydroxide (NaOH) is approximately 40 g/mole. So the amount of sodium hydroxide needed in grams is moles x molecular weight = 0.2459 moles x 40 g/mole = 9.836 g. So, approximately 9.836 grams of sodium hydroxide are required to make a 701 ml solution with a concentration of 0.3506 M.