How Many Gold Atoms are in a 0.255 Ounce, 18k Gold Bracelet?

Question: How many gold atoms are in an 0.255 ounce, 18k gold bracelet? Final answer: The number of gold atoms in the 0.255 ounce, 18k gold bracelet is approximately 1.654 x 10^22 atoms.

Calculation:

To find the number of gold atoms in the 0.255 ounce, 18k gold bracelet, we need to calculate the number of moles of gold in the bracelet and then convert it to atoms.

Step 1: Calculate the mass of gold in the bracelet.

Mass of gold = 0.255 ounce x 75% = 0.19125 ounce

Step 2: Convert the mass of gold to grams.

1 ounce = 28.35 grams Mass of gold = 0.19125 ounce x 28.35 grams/ounce = 5.421 grams

Step 3: Calculate the number of moles of gold.

Molar mass of gold = 197 grams/mole Number of moles of gold = 5.421 grams / 197 grams/mole = 0.0275 mole

Step 4: Convert the number of moles to the number of atoms using Avogadro's number.

Avogadro's number = 6.022 x 10^23 atoms/mole Number of gold atoms = 0.0275 mole x 6.022 x 10^23 atoms/mole = 1.654 x 10^22 atoms

Conclusion:

Therefore, there are approximately 1.654 x 10^22 gold atoms in a 0.255 ounce, 18k gold bracelet.

← Net charge calculation of peptide aigneck at ph 4 3 Exciting moles calculation of magnesium chloride →

More Posts: