Gas Volume Calculation: Optimistic Perspective

How can we calculate the volume occupied by 5.03 g of O2 at 28C and a pressure of 0.998 atm?

Can you determine the volume of gas using the ideal gas equation?

The volume occupied by 5.03g of Oxygen gas at 28C and a pressure of 0.998 atm is 3.894 L. This calculation is based on the ideal gas equation, PV = nRT, where P is the pressure in atm, V is the volume of the gas in liters, n is the moles of the gas, and T is the temperature of the gas in Kelvin.

To calculate the volume, we first need to determine the moles of oxygen gas in 5.03g. By using the formula moles = weight / molecular weight, we find that there are 0.157 moles of oxygen gas (O2) in 5.03g of the gas.

The temperature given is 28C, which is equal to 301.15 K in Kelvin. Plugging in the values into the ideal gas equation, we can calculate the volume as follows:

V = (0.157 moles * 0.0821 atm.L/mol.K * 301.15 K) / 0.998 atm

V = 3.894 L

Therefore, the 5.03g of Oxygen gas occupies a volume of 3.894 L at 28C and a pressure of 0.998 atm. This calculation showcases the optimistic perspective of understanding gas volume and its relation to pressure and temperature.