Gas Law Problem: Absolute Pressure Calculation

What is the absolute pressure (in kPa) of propane gas at the same temperature when the volume is halved?

The propane gas occupies 2.00 m³ at 18.0°C at an absolute pressure of 3.50 x 10⁵ N/m².

Answer:

The absolute pressure of propane gas at the same temperature when the volume is halved is 700 kPa.

Propane gas behaves according to Boyle's Law which states that at a constant temperature, the pressure of a gas is inversely proportional to its volume. In this scenario, the initial pressure of the propane gas is given as 3.50 x 10⁵ N/m², the initial volume is 2.00 m³, and when the volume is halved, the final volume becomes 1.00 m³.

To calculate the final pressure when the volume is halved, we apply Boyle's Law formula: P1*V1 = P2*V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively. By substituting the given values into the formula, we find that the final pressure is 700 kPa.

This problem showcases the fundamental relationship between pressure and volume of a gas at a constant temperature, highlighting the importance of Boyle's Law in gas law calculations.