Determining Atom Composition of Alloy with Pb and Sn
What is the composition, in atom percent, of an alloy that consists of 4.5 wt% Pb and 95.5 wt% Sn?
Can you determine the atom percent composition of an alloy made up of 4.5 wt% Pb and 95.5 wt% Sn?
Composition of the Alloy:
The composition, in atom percent, of the alloy is 2.18% Pb and 80.44% Sn.
When determining the atom composition of an alloy with 4.5 wt% Pb and 95.5 wt% Sn, it is important to convert the weight percentages to atomic percentages by dividing the weight percent by the atomic weight of each element.
First, calculate the atomic weight of Pb and Sn:
Atomic weight of Pb = 207.19 g/mol
Atomic weight of Sn = 118.71 g/mol
Next, convert the given weight percentages to atomic percentages:
Percent by weight (wt%) of Pb = 4.5%
Atomic percent (at%) of Pb = (4.5 / 207.19) × 100 = 0.0218 × 100 = 2.18%
Percent by weight (wt%) of Sn = 95.5%
Atomic percent (at%) of Sn = (95.5 / 118.71) × 100 = 0.8044 × 100 = 80.44%
Therefore, the composition, in atom percent, of the alloy is 2.18% Pb and 80.44% Sn. This means that the alloy is composed of approximately 2.18% Pb atoms and 80.44% Sn atoms in terms of atom percent.