Chemical Stoichiometry: Volume Calculation Example

How do we determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl?

a. 180 mL
b. 1100 mL
c. 0.18 mL
d. 448 mL

Final answer:

Answer:

To determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl, we can use the concept of stoichiometry. The correct answer is option c. 0.18 mL.

Explanation:

To determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl, we can use the concept of stoichiometry. From the balanced chemical equation:

NaOH + HCl → NaCl + H2O

We can see that the mole ratio between NaOH and HCl is 1:1. Therefore, the number of moles of HCl is equal to the number of moles of NaOH. To find the number of moles of HCl, we use the equation:

Moles = Molarity x Volume (in liters)

Given that the volume of HCl is 448 mL (or 0.448 L) and the molarity is 0.600 M, we can solve for the number of moles of HCl:

Moles HCl = 0.600 M x 0.448 L = 0.2688 mol HCl

Since the mole ratio between NaOH and HCl is 1:1, the number of moles of NaOH needed is also 0.2688 mol NaOH. Now, we can use the molarity of NaOH to find the volume:

Given that the molarity of NaOH is 1.5 M, we can use the equation:

Volume = Moles / Molarity

Substituting the values, we get:

Volume NaOH = 0.2688 mol / 1.5 M = 0.1792 L = 179.2 mL

Therefore, the correct answer is option c. 0.18 mL.