Chemical Reaction Stoichiometry: Calculating Mass of Reactant
How many grams of sodium would need to react with 4.5 moles of chloride?
A. 15.6 g
B. 103.5 g
C. 5.1 g
D. 157.55 g
E. 53.5 g
Answer:
Taking into account the reaction stoichiometry, 103.5 grams of Na⁺ is required to react with 4.5 moles of chloride.
In order to determine the amount of sodium needed to react with 4.5 moles of chloride, we must understand the concept of reaction stoichiometry.
Reaction Stoichiometry
In the given balanced equation:
Na⁺ + Cl⁻ → NaCl
According to reaction stoichiometry:
- Na⁺: 1 mole
- Cl⁻: 1 mole
- NaCl: 1 mole
The molar masses of the compounds are:
- Na⁺: 23 g/mole
- Cl⁻: 35.45 g/mole
- NaCl: 58.45 g/mole
Calculating the mass quantities of each compound involved in the reaction:
- Na⁺: 1 mole × 23 g/mole = 23 grams
- Cl⁻: 1 mole × 35.45 g/mole = 35.45 grams
- NaCl: 1 mole × 58.45 g/mole = 58.45 grams
Calculating Mass of Sodium Ions Required
We can use the rule of three to find the mass of Na⁺ needed:
mass of Na⁺ = (4.5 moles of Cl⁻ × 23 grams of Na⁺) ÷ 1 mole of Cl⁻
mass of Na⁺ = 103.5 grams
Therefore, 103.5 grams of Na⁺ is required to react with 4.5 moles of chloride.