Calculating the Mass of a Substance in a Solution
A solution contains ________ g of a substance.
1) 6.00 g
2) 14.4 g
3) 156 g
4) 15.6 g
5) 43.3 g
Final answer:
The mass of solute in 0.500 L of 0.30 M glucose is calculated by first determining the number of moles of glucose present, then using its molar mass to find the mass, which is 27 g.
Explanation:
To find the mass of solute in 0.500 L of 0.30 M glucose, C6H12O6, you would use the following calculation:
- Determine the number of moles of glucose in 0.500 L of solution by multiplying the volume of the solution by its molarity (M), i.e., 0.500 L × 0.30 M.
- Find the molar mass of glucose by adding the atomic masses of its constituent atoms: C6H12O6 = (6 × 12.01) + (12 × 1.01) + (6 × 16.00).
- Calculate the mass of glucose by multiplying the number of moles from step 1 by the molar mass from step 2.
The final answer from the example given is 27 g of glucose, demonstrating the application of stoichiometry in determining the mass of a solute in a solution.
What is the final mass of the substance in the solution? The final mass of the substance in the solution is 27 grams.