Calculating Heat Gained by Ice

How much heat is gained by 1.25 grams of ice?

Answer: Heat gained by 1.25 grams of ice is 250 joules

Understanding Heat Transfer in Ice

Heat transfer is the process of energy moving from a warmer object to a cooler object. In this case, we are calculating the heat gained by ice when it goes through a change in temperature.

Formula for Calculating Heat

The formula used to calculate heat transfer is Q = mcΔT, where Q represents the heat gained or lost, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Applying the Formula to Ice

For the given scenario, we have 1.25 grams of ice. The specific heat of ice is 2.05 joules/gram. The change in temperature for ice occurs when it goes from its freezing point at 0 degrees Celsius (273.15 K) to 100 degrees Celsius (373.15 K) in the form of water.

By substituting the values into the formula, we can calculate the heat gained by the ice as follows:

Q = 1.25 * 2.0 * 100 = 250 joules

Conclusion

In conclusion, 1.25 grams of ice gains 250 joules of heat when it undergoes a temperature change. Understanding the principles of heat transfer is vital in various scientific fields and applications.