Atoms Calculation in 191g of Calcium

How many atoms are in 191g of calcium?

Is it possible to determine the number of atoms in 191g of calcium?

Answer:

The number of atoms in 191g of calcium is 2.869 x 10^24 atoms Ca.

When we have 191g of calcium, we can calculate the number of atoms present in this sample using the concept of moles and Avogadro's number. First, we convert the given mass of calcium to moles of calcium by utilizing its molar mass, which is 40.08g/mol according to the periodic table:

191g Ca x (1 mol Ca / 40.08g Ca) = 4.765 mol Ca

Then, by using Avogadro's number (6.022 x 10^23 particles/mol), we can calculate the number of atoms of calcium present:

4.765 mol Ca x (6.022 x 10^23 / 1 mol Ca) = 2.869 x 10^24 atoms Ca

Therefore, in 191g of calcium, there are 2.869 x 10^24 atoms of calcium. This calculation showcases the relationship between mass, moles, and the number of atoms, providing a deeper understanding of the composition of substances at the atomic level.