Actual Yield of Aluminum Chloride in a Chemical Reaction

What is the actual yield of aluminum chloride in a chemical reaction between aluminum hydroxide and hydrogen chloride gas?

a. 15.6 g b. 14.43 g c. 14.43% d. 92.5%

Answer:

The actual yield of aluminum chloride is b) 14.43 g.

When a reaction occurs between aluminum hydroxide and hydrogen chloride gas, it produces aluminum chloride and water. In this specific reaction, the percent yield is given as 92.5%. The initial weight of aluminum hydroxide used in the reaction is 15.6 g.

To calculate the actual yield of aluminum chloride, we first need to determine the theoretical yield. This can be done by converting the given mass of aluminum hydroxide to moles, following the balanced equation, and then converting moles of aluminum chloride produced. By multiplying the percent yield by the theoretical yield, we can find the actual yield.

In this case, the correct answer is b) 14.43 g. This means that in the given reaction, 14.43 grams of aluminum chloride will be produced as the actual yield.

Understanding the concept of actual yield in chemical reactions is crucial for determining the efficiency and success of a reaction. It helps in evaluating the overall performance and allows for adjustments to be made for future experiments.